H - And Then There Was 5

Your friend Mike is arguing with a classmate Chris over what the last digit in π is. (You and I know there is no such thing, but Chris simply isn't to be dissuaded.) Mike's argument is as flawed as it is entertaining: given any digit in π that you look at, either the number itself is a 5 or there is a 5 that occurs after that digit.

Cute, but that same argument is true of any digit, at least for the portion of π that has been calculated. Luckily, you're not being asked to actually prove anything; Mike just wants you to use your "computer skills" to give him some sample data for him to use to support his case.

Your friend wants a large sampling of places of π and wants to show that his argument holds true. For each test case, you will be given an offset into the digits of π (P) and a single digit (D).

He wants to you find the Qth and Rth digits of π given that:

• Q is the lowest offset such that Q >= P and the Qth digit of π equals D
• R is the lowest offset such that R > Q and the Rth digit of π equals 5

For example, if P is 3 and D is 2, Q would be 6 and R would be 8, and the Qth and Rth digits of π would be 2 and 5 respectively.

              P     Q   R
Offset: 0 1 2 3 4 5 6 7 8 9 10 11 ...
Value:  3 1 4 1 5 9 2 6 5 3  5  8 ...

4
3 2
123456 6
999999 8
765432 7

2 5
6 5
8 5
7 5